Promethium(III) bromide
Promethium(III) bromide is an inorganic compound, with the chemical formula of PmBr3. It is radioactive salt. It is a crystal of the hexagonal crystal system, with the space group of P63/mc (No. 176).
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| IUPAC name
 Promethium(III) bromide  | |
| Identifiers | |
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| Properties | |
| PmBr3 | |
| Molar mass | 385 | 
| Appearance | Red solid[1] | 
| Melting point | 624[1] | 
| Related compounds | |
Other anions  | 
Promethium(III) fluoride Promethium(III) chloride Promethium(III) iodide  | 
Other cations  | 
Neodymium(III) bromide Samarium(III) bromide  | 
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa). 
Infobox references  | |
Preparation
    
Promethium(III) bromide can be obtained by reacting hydrogen bromide and promethium(III) oxide:[2]
- Pm2O3 + 6 HBr —500°C→ 2 PmBr3 + 3 H2O
 
Promethium(III) bromide hydrate cannot be heated to form its anhydrous form. Instead it decomposes in water to form promethium oxybromide:[3]
- PmBr3 + H2O(g) → PmOBr + 2 HBr
 
References
    
- Cotton, Simon (2006). Lanthanide And Actinide Chemistry. John Wiley & Sons. p. 117. ISBN 978-0-470-01006-8.
 - W. R. Wilmarth, G. M. Begun, R. G. Haire, et al. Raman spectra of Pm2O3, PmF3, PmCl3, PmBr3 and PmI3. Journal of Raman Spectroscopy, 2005. 19(4)
 - Wishnevsky, V; Theissig, W; Weigel, F (June 1984). "The vapor phase hydrolysis of lanthanide(III) bromides IV: Heat and free energy of the reaction PmBr3(s) + H2O(g) = PmOBr(s) + 2HBr(g)". Journal of the Less Common Metals. 99 (2): 321–329. doi:10.1016/0022-5088(84)90230-3.
 
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