1836 United States presidential election in Virginia
The 1836 United States presidential election in Virginia took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 23 representatives, or electors to the Electoral College, who voted for President and Vice President.
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| Elections in Virginia |
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Virginia voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Virginia by a margin of 13.29%. While Van Buren's national running mate was Richard Mentor Johnson, the Virginia Democratic electors refused to support his candidacy and voted for William Smith of South Carolina.
Results
| United States presidential election in Virginia, 1836[1] | |||||
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| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic | Martin Van Buren | 30,556 | 56.64% | 23 | |
| Whig | Hugh L. White | 23,384 | 43.35% | 0 | |
| N/A | Others | 5 | 0.01% | 0 | |
| Totals | 53,945 | 100.0% | 23 | ||
References
- "1836 Presidential General Election Results - Virginia". U.S. Election Atlas. Retrieved April 12, 2013.
State and district results of the 1836 United States presidential election | ||
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