1836 United States presidential election in Connecticut
The 1836 United States presidential election in Connecticut took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.
| ||||||||||||||||||||||||||
|
Elections in Connecticut |
---|
Connecticut voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Connecticut by a narrow margin of 1.3%.
As a result of his win, Van Buren also became the first Democratic presidential candidate to carry Connecticut.
Results
1836 United States presidential election in Connecticut[1] | |||||
---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Martin Van Buren | 19,294 | 50.65% | 8 | |
Whig | William Henry Harrison | 18,799 | 49.35% | 0 | |
Totals | 38,093 | 100.0% | 8 | ||
References
- "1836 Presidential General Election Results - Connecticut". U.S. Election Atlas. Retrieved August 4, 2012.
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.