1896 United States presidential election in Illinois
The 1896 United States presidential election in Illinois took place on November 3, 1896. All contemporary 45 states were part of the 1896 United States presidential election. State voters chose 24 electors to the Electoral College, which selected the president and vice president.
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Elections in Illinois |
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Illinois was won by the Republican nominees, former Ohio Governor William McKinley and his running mate Garret Hobart of New Jersey. They defeated the Democratic nominee, former U.S. Representative from Nebraska William Jennings Bryan and his running mate Arthur Sewall. McKinley won the state by a margin of 12.98%.
Bryan would lose Illinois to McKinley again four years later and would later lose the state again in 1908 to William Howard Taft.
Results
1896 United States presidential election in Illinois[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Republican | William McKinley | 607,130 | 55.66% | 24 | |
Democratic | William Jennings Bryan | 465,613 | 42.68% | 0 | |
Prohibition | Joshua Levering | 9,796 | 0.90% | 0 | |
National Democratic | John M. Palmer | 6,390 | 0.59% | 0 | |
Socialist Labor | Charles Matchett | 1,147 | 0.11% | 0 | |
National Prohibition | Charles Bentley | 793 | 0.07% | 0 | |
Totals | 1,090,869 | 100.00% | 24 | ||
Voter turnout | — |
Chicago results
1896 United States presidential election in Chicago[2] | |||||
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Party | Candidate | Votes | Percentage | ||
Republican | William McKinley | 198,749 | 57.54% | ||
Democratic | William Jennings Bryan | 142,206 | 41.17% | ||
National Democratic | John M. Palmer | 2,089 | 0.60% | ||
Prohibition | Joshua Levering | 1,558 | 0.45% | ||
Socialist Labor | Charles Matchett | 647 | 0.19% | ||
National Prohibition | Charles Bentley | 136 | 0.04% | ||
Totals | 345,483 | 100.00% | |||
Notes
References
- Dave Leip's U.S. Election Atlas; Presidential General Election Results – Illinois
- "COOK COUNTY". The Chicago Tribune. November 4, 1896. Retrieved August 11, 2023.
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