1844 United States presidential election in Alabama
The 1844 United States presidential election in Alabama took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.
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| Elections in Alabama |
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Alabama voted for the Democratic candidate, James K. Polk, over Whig candidate Henry Clay. Polk won Alabama by a margin of 17.98%.
Results
| 1844 United States presidential election in Alabama[1] | ||||||||
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| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | James K. Polk of Tennessee | George M. Dallas of Pennsylvania | 37,401 | 58.99% | 9 | 100.00% | ||
| Whig | Henry Clay of Kentucky | Theodore Frelinghuysen of New York | 26,002 | 41.01% | 0 | 0.00% | ||
| Total | 63,403 | 100.00% | 9 | 100.00% | ||||
References
- "1844 Presidential General Election Results - Alabama". U.S. Election Atlas. Retrieved December 23, 2013.
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