1788–89 United States presidential election in Delaware

The 1788–89 United States presidential election in Delaware took place on January 7, 1789 as part of the 1788–1789 United States presidential election to elect the first President. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

1788–1789 United States presidential election in Delaware

January 7, 1789
 
Nominee George Washington John Jay
Party Independent Independent
Home state Virginia New York
Electoral vote 3 3
Popular vote 685 0
Percentage 100.00% 0.00%

President before election

Office established

Elected President

George Washington
Independent

George Mitchell, John Baning, and Gunning Bedford Jr. served as electors. George Washington and John Jay both received three electoral votes.[1]

Results

United States presidential election in Delaware, 1789
Party Candidate Votes Percentage Electoral votes
Independent George Washington 685 100.00% 3
Totals 685 100.00% 3

See also

References

  1. Jensen & Becker 1976, p. xxviii.

Works cited

  • Jensen, Merrill; Becker, Robert, eds. (1976). The First Federal Elections 1788-1790: Congress, South Carolina, Pennsylvania, Massachusetts, New Hampshire. Vol. 1. University of Wisconsin Press. ISBN 0299066908.


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