1948 United States presidential election in Delaware

The 1948 United States presidential election in Delaware took place on November 2, 1948, as part of the 1948 United States presidential election. State voters chose three[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

1948 United States presidential election in Delaware

November 2, 1948[1]
All 3 Delaware votes to the Electoral College
Nominee Thomas E. Dewey Harry S. Truman Party Republican Democratic Home state New York Missouri Running mate Earl Warren Alben W. Barkley Electoral vote 3 0 Popular vote 69,588 67,813 Percentage 50.04% 48.76%
County Results Dewey   50-60% Truman   40-50%
President before election Harry S. Truman Democratic Elected President Harry S. Truman Democratic

Elections in Delaware
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Wilmington Mayoral elections 2012 2016 2020

Delaware was won by Governor Thomas Dewey (R–New York), running with Governor Earl Warren, with 50.04% of the popular vote, against incumbent President Harry S. Truman (D–Missouri), running with Senator Alben W. Barkley, with 48.76% of the popular vote.[3][4] This is the last time that New Castle County did not back the statewide winner and when the Democratic candidate would win a presidential election without Delaware.

This election marks one of three times in the 20th century that the state voted for the losing candidate, along with 1932 and 1916. As this was the last election until 2000 when Delaware failed to support the overall winner of the presidency, and the electoral college after which the state has leaned Democratic. However, it has since voted for the popular vote loser only once, in 2004.