1808 United States presidential election in Delaware
The 1808 United States presidential election in Delaware took place between 4 November and 7 December 1808, as part of the 1808 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.
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| Elections in Delaware |
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Delaware cast three electoral votes for the Federalist candidate Charles C. Pinckney over the Democratic-Republican candidate James Madison. These electors were elected by the Delaware General Assembly, the state legislature, rather than by popular vote. The three electoral votes for Vice president were cast for Pinckney's running mate Rufus King from New York.[1]
Results
| 1808 United States presidential election in Delaware[2] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Federalist | Charles C. Pinckney | – | – | 3 | |
| Democratic-Republican | James Madison | – | – | 0 | |
| Totals | – | – | 3 | ||
References
- "1808 Presidential General Election Results". U.S. Election Atlas. Retrieved July 9, 2023.
- "1808 Presidential Election". 270towin.com. Retrieved July 9, 2023.
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