Robinwood, Maryland

Robinwood is located at 39°37′41″N 77°40′8″W (39.627939, −77.668777).[2]

According to the United States Census Bureau, the CDP has a total area of 3.8 square miles (9.8 km²), all land.

As of the census[4] of 2000, there were 4,731 people, 1,918 households, and 1,294 families residing in the CDP. The population density was 1,254.2 inhabitants per square mile (484.2/km²). There were 1,985 housing units at an average density of 526.2 per square mile (203.2/km²). The racial makeup of the CDP was 87.93% White, 6.34% African American, 0.19% Native American, 2.64% Asian, 0.19% Pacific Islander, 0.99% from other races, and 1.71% from two or more races. Hispanic or Latino of any race were 2.22% of the population.

There were 1,918 households, out of which 32.5% had children under the age of 18 living with them, 55.6% were married couples living together, 8.7% had a female householder with no husband present, and 32.5% were non-families. 25.5% of all households were made up of individuals, and 9.7% had someone living alone who was 65 years of age or older. The average household size was 2.45 and the average family size was 2.97.

In the CDP, the population was spread out, with 25.0% under the age of 18, 8.3% from 18 to 24, 29.8% from 25 to 44, 24.0% from 45 to 64, and 12.9% who were 65 years of age or older. The median age was 36 years. For every 100 females, there were 91.5 males. For every 100 females age 18 and over, there were 89.6 males.

The median income for a household in the CDP was $50,615, and the median income for a family was $62,965. Males had a median income of $38,000 versus $30,404 for females. The per capita income for the CDP was $26,608. About 2.6% of families and 6.3% of the population were below the poverty line, including 6.4% of those under age 18 and 14.8% of those age 65 or over.