1993 Virginia Slims of Houston – Doubles

Patty Fendick and Mary Joe Fernández were the defending champions, but none competed this year.

Doubles
1993 Virginia Slims of Houston
Champions
Runners-up
Score6–3, 5–7, 7–6(9–7)
Draw16 (1Q/1LL)
Seeds4

Katrina Adams and Manon Bollegraf won the title by defeating Eugenia Maniokova and Radka Zrubáková 6–3, 5–7, 7–6(9–7) in the final.[1]

Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 United States K Adams
Netherlands M Bollegraf
6 77
Q 2 60 1 United States K Adams
Netherlands M Bollegraf
6 6
Austria P Ritter
Netherlands C Vis
6 77 1 3
1 61 1 United States K Adams
Netherlands M Bollegraf
6 6
4 United Kingdom J Durie
New Zealand J Richardson
61 6 6 2 2
77 3 2 4 3 0
2 66 Bulgaria K Maleeva
Switzerland M Maleeva-Fragnière
6 6
Bulgaria K Maleeva
Switzerland M Maleeva-Fragnière
6 78 1 United States K Adams
Netherlands M Bollegraf
6 5 79
Russia E Maniokova
Slovakia R Zrubáková
6 6 3 7 67
WC United States Kellie Dorman-Tyrone
Republic of Ireland Philippa Palmer
1 1 Russia E Maniokova
Slovakia R Zrubáková
6 2 79
3 2 3 4 6 67
3 Germany K Kschwendt
Argentina F Labat
6 6 Russia E Maniokova
Slovakia R Zrubáková
6 6
Netherlands I Driehuis
Mexico L Novelo
6 3 6 2 4 4
4 6 2 3 63
65 3 2 Italy S Cecchini
Argentina P Tarabini
6 77
2 Italy S Cecchini
Argentina P Tarabini
77 6

References

  1. "Tennis WTA Houston Doubles 1993 Scores". Tennis 24. Retrieved June 29, 2023.
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