1860 United States presidential election in Oregon
The 1860 United States presidential election in Oregon took place on November 6, 1860, as part of the 1860 United States presidential election. Oregon voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.
![]() | |||||||||||||||||||||||||||||||||
| |||||||||||||||||||||||||||||||||
| |||||||||||||||||||||||||||||||||
![]() County Results
| |||||||||||||||||||||||||||||||||
|
Elections in Oregon |
---|
![]() |
Oregon voted in its first ever presidential election, having become the 33rd state on February 14, 1859. The state was won by Illinois Representative Abraham Lincoln (RโKentucky), running with Senator Hannibal Hamlin, with 36.20% of the popular vote, against the 14th Vice President of the United States John C. Breckinridge (SDโKentucky), running with Senator Joseph Lane, with 34.37% of the popular vote and Senator Stephen A. Douglas (DโIllinois), running with 41st Governor of Georgia Herschel V. Johnson, with 27.99% of the popular vote.
Oregon was the only state where the first and second-place finishers matched the first and second place national finishers in the electoral college (Lincoln first, then Breckenridge in second).
Results
Party | Candidate | Votes | % | |
---|---|---|---|---|
Republican | Abraham Lincoln | 5,344 | 36.20% | |
Southern Democratic | John C. Breckinridge | 5,074 | 34.37% | |
Democratic | Stephen A. Douglas | 4,131 | 27.99% | |
Constitutional Union | John Bell | 212 | 1.44% | |
Total votes | 14,761 | 100% |