1819 Rhode Island gubernatorial election
The 1819 Rhode Island gubernatorial election was an uncontested election held on April 21, 1819 to elect the Governor of Rhode Island. Nehemiah Rice Knight, the incumbent Governor and Democratic-Republican nominee, was the only candidate and so won with 100% of the vote.
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General election
| Elections in Rhode Island |
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Candidates
- Nehemiah Rice Knight, the incumbent Governor since 1817.[2]
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Democratic-Republican | Nehemiah Rice Knight (incumbent) | 2,670 | 100% | ||
| Majority | 2,670 | 100% | |||
| Democratic-Republican hold | Swing | ||||
County results
| County[3] | Nehemiah Knight
Democratic-Republican |
Total votes | |
|---|---|---|---|
| # | % | ||
| Bristol | 175 | 100% | 175 |
| Kent | 473 | 100% | 473 |
| Newport | 518 | 100% | 518 |
| Providence | 1,056 | 100% | 1,056 |
| Washington | 448 | 100% | 448 |
| Totals | 2,670 | 100% | 2,670 |
References
- "Election". The Rhode-Island Republican. Newport, R.I. April 21, 1819. p. 2. Retrieved October 24, 2021.
- "KNIGHT, Nehemiah Rice". Biographical Directory of the United States Congress. Retrieved June 2, 2022.
- "Rhode Island 1819 Governor". A New Nation Votes: American Election Returns 1787-1825. January 11, 2012. Retrieved June 2, 2022.
- Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson: McFarland & Company. p. 232. ISBN 9780786414390.
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