2018 Silicon Valley Classic – Doubles
Abigail Spears and CoCo Vandeweghe were the defending champions, but chose not to participate this year.
| Doubles | |
|---|---|
| 2018 Silicon Valley Classic | |
| Champions | |
| Runners-up | |
| Score | 6–4, 6–1 |
| Draw | 15 |
| Seeds | 4 |
Latisha Chan and Květa Peschke won the title, defeating Lyudmyla and Nadiia Kichenok in the final, 6–4, 6–1.
Seeds
Latisha Chan /
Květa Peschke (champions)
Mihaela Buzărnescu /
Heather Watson (semifinals)
Lyudmyla Kichenok /
Nadiia Kichenok (final)
Miyu Kato /
Makoto Ninomiya (semifinals)
Draw
Key
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
Draw
| First round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
| 1 | w/o | ||||||||||||||||||||||||||
| 4 | 1 | ||||||||||||||||||||||||||
| 6 | 6 | 1 | 6 | 6 | |||||||||||||||||||||||
| 4 | 1 | 7 | [10] | 4 | 1 | 4 | |||||||||||||||||||||
| 6 | 5 | [4] | 4 | 6 | 6 | ||||||||||||||||||||||
| 4 | 4 | 4 | 2 | ||||||||||||||||||||||||
| 6 | 6 | 1 | 6 | 6 | |||||||||||||||||||||||
| 3 | 3 | 3 | 4 | 1 | |||||||||||||||||||||||
| 6 | 6 | 6 | 2 | [6] | |||||||||||||||||||||||
| 6 | 3 | [7] | 3 | 1 | 6 | [10] | |||||||||||||||||||||
| 3 | 4 | 6 | [10] | 3 | 6 | 3 | [10] | ||||||||||||||||||||
| 3 | 2 | 2 | 4 | 6 | [8] | ||||||||||||||||||||||
| 6 | 6 | 5 | 2 | ||||||||||||||||||||||||
| WC | 3 | 3 | 2 | 7 | 6 | ||||||||||||||||||||||
| 2 | 6 | 6 | |||||||||||||||||||||||||
External links
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.