2016 Trophée des Alpilles – Doubles

Doubles
Doubles
2016 Trophée des Alpilles
Champions	Ken Skupski; Neal Skupski
Runners-up	David O'Hare; Joe Salisbury
Score	6–7(5–7), 6–4, [10–5]

Ken and Neal Skupski were the defending champions and successfully defended their title, defeating David O'Hare and Joe Salisbury 6–7^(5–7), 6–4, [10–5] in the final.

Seeds

Purav Raja / Divij Sharan (first round)
Ken Skupski / Neal Skupski (champions)
Konstantin Kravchuk / Artem Sitak (first round)
Grégoire Barrère / Albano Olivetti (semifinals)

Draw

Key

First round					Quarterfinals				Semifinals				Final

1	P Raja D Sharan	6	2	[5]
	D O'Hare J Salisbury	3	6	[10]		D O'Hare J Salisbury	6	6
PR	M Bachinger P Gojowczyk	6²	6	[11]	PR	M Bachinger P Gojowczyk	3	3
	D Medvedev M Viola	7⁷	4	[9]						D O'Hare J Salisbury	6	6
4	G Barrère A Olivetti	7¹⁰	7¹⁰						4	G Barrère A Olivetti	2	4
WC	M Janvier R Jouan	6⁸	6⁸		4	G Barrère A Olivetti	6	7⁷
	K Coppejans Y Mertens	6	3	[6]		T Draganja A Menéndez-Maceiras	4	6³
	T Draganja A Menéndez-Maceiras	2	6	[10]										D O'Hare J Salisbury	7⁷	4	[5]
	M Copil S Stakhovsky	6	6										2	K Skupski N Skupski	6⁵	6	[10]
WC	Alexandre Buchner Boris Vermet	1	3			M Copil S Stakhovsky
	I Sabanov M Sabanov	2	6	[10]		I Sabanov M Sabanov	w/o
3	K Kravchuk A Sitak	6	3	[6]						I Sabanov M Sabanov	2	2
WC	Cyril Respaut Nathan Seateun	2	4						2	K Skupski N Skupski	6	6
	A Pavić A Šetkić	6	6			A Pavić A Šetkić	3	6¹
	R Bemelmans J De Loore	6²	4		2	K Skupski N Skupski	6	7⁷
2	K Skupski N Skupski	7⁷	6

References

Main Draw

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