1890 Idaho gubernatorial election
The 1890 Idaho gubernatorial election was held on 1 October 1890, in order to elect the first Governor of Idaho upon Idaho acquiring statehood in July 1890. Incumbent Republican Governor of the Idaho Territory George L. Shoup defeated Democratic nominee Benjamin Wilson.[1]
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 County results Shoup: 50–60% 60–70% Wilson: 50–60% | |||||||||||||||||
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| Elections in Idaho |
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General election
On election day, 1 October 1890, Republican nominee George L. Shoup won the election by a margin of 2,314 votes against his opponent Democratic nominee Benjamin Wilson, thereby retaining Republican control over the new office of Governor. Shoup was sworn in as the first Governor of the new state of Idaho on 8 December 1890.[2]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | George L. Shoup (incumbent[lower-alpha 1]) | 10,262 | 56.35% | |
| Democratic | Benjamin Wilson | 7,948 | 43.65% | |
| Total votes | 18,210 | 100.00% | ||
| Republican hold | ||||
Notes
- Incumbent governor of Idaho Territory.
References
- "George L. Shoup". National Governors Association. Retrieved May 12, 2023.
- "ID Governor". ourcampaigns.com. September 26, 2005. Retrieved May 12, 2023.
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